The anodic oxidation of solid Pb in H 2 SO 4 to form PbSO 4 has been investigated by rotating disc, potentiostatic pulse and ac impedance measurements. Therefore oxidation number of Pb is +2. Also, the answer would not be +10 if what you had said was correct (about the sulfur ion). SO4 has charge of -2. It is suggested that a precipitation mechanism to form PbSO 4 occurs under some conditions prior to the solid state … What is the oxidation number of phosphorous in the H3PO2 molecule? ... Pb PbO2 PbSO4 H2O H2SO4. Identify the products and the reactants, and then their oxidation numbers. Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions: Pb(s) + PbO 2 (s) + 2H 2 SO 4 (aq) → 2PbSO 4 (s) + 2H 2 O(l) Pb. Therefore x+6-8=0. I went by the rule of the most electronegative atom getting their typical oxidation state (so O was assigned -2 (total -8)...then S was assigned -2...and finally Pb was given +10 to balance the molecule). Asked by | 25th Mar, 2009, 06:56: PM. Therefore oxidation number of Pb in PbSO 4 … But Sulfate ion has -2 charge. The rates of PbSO4 formation on the Pb–0.08 mass% Ca–Sn alloys, which are the choice materials for grids in the valve-regulated lead–acid battery (VRLA), were inhibited by the presence of Sn. Oxidation number of Pb is +2 Oxidation number of S=+6. pb +2 s-2 + h +1 2 o-1 2 → pb +2 s +6 o-2 4 + h +1 2 o-2 b) Identify and write out all redox couples in reaction. PbSO 4 salt does not have an overall charge. Could you tell me how you went about getting the oxidation number for Pb in PbSO4? The system is compared with measurements on Pb(Hg) in H 2 SO 4 and with Pb(Hg), Hg, solid Pb in HClO 4 solution. PbSO4 --> Pb2+ + SO4 2- (A net dissociation reaction of the salt) SO4 has an oxidation number of -2. what is the oxidation number of pb in pbso4. So, Pb is at +2 oxidation state. Sulfide ion is at -2 oxidation state. Expert Answer: Let the oxidation number of Pb=x. Pb in PbSO4 : +2. Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). Figuring out why these numbers are the way they are takes a fair amount of work. In order to make the compound neutral, Pb must be +2. H in H2 : 0. The total should equal when you add all oxidation numbers: Pb + (-2) = 0 ----> Pb = +2. How to calculate oxidation number of Pb in PbSO4?And Explain? Oxidation = number goes down Reduction = number goes up. It can only be +2, or +4. +1 +3 0-1 +2 +1. If you consider oxidation as the loss of electrons and gain of oxidation number, and reduction as the gain of electrons and decrease in oxidation number, the oxidation states are as follows: Pb : 0 (Elementary state) H in H2SO4 : +2. To neutral that -2 charge, +2 charge should be there and it is given by Pb 2+ ion. Oxidation number of O=-2. You are correct that oxidation is the loss of electrons and reduction is the gaining of electrons. Sum of all oxidation number =0. Check to see if the oxidation numbers show oxidation or reduction. H2O2 + PbS --> PbSO4 + H2O. Lead, being a metal, has very set oxidation numbers.